Question

What is the latus rectu,m of equation 9x^2- 6x+36y+19=0
Options are
A.36
B.9
C.6
D.4

Answer 1

Answer:

Let `L_1` be the length of the common chord of the curves

`x^2 + y^2=9` and `y^2= 8x,` and `L_2` be the length of the latus rectum

of `y^2=8x,`

then: (A) `L_1 lt L_2` (B) `L_1/L_2=sqrt2` (C) `L_1gtL_2` (D) `L_1=L_2`:

Answer 2

Answer:

the answer is option D. 4

Step-by-step explanation:

9x2−6x+19= −36y

⇒(3x−1)^2=−36y−18=−36 (y+1/2)

⇒9(x−1/3^)2=− 36(y+1/2)

Hence length of latus rectum is 4