What is the LCM of (p+q)(p+r) , (q+r)(r+p) and (r+p)(p+q)?
Answers
Answer:The common factors among two monomials are 2, 2, a, a, b; other than these common factors, in the first monomial the extra factors are b, b and in the second monomial the extra factors are 3, a.
Therefore, the required L.C.M. = common factors among two monomials × extra common factors among two monomials.
= (2 × 2 × a × a × b)(3 × a × b × b)
= 4a2b × 3ab2
= 12a3b3
Hence, the lowest common multiple of the monomials 4a2b3 and 12a3b = 12a3b3.
2. Find the L.C.M of the monomials 6p2q2, 15p3q and 9p2q3r.
Solution:
The L.C.M. of numerical coefficients = The L.C.M. of 6, 15 and 9.
Since, 6 = 2 × 3 = 21 × 31, 15 = 3 × 5 = 31 × 51 and 9 = 3 × 3 = 32
Therefore, the L.C.M. of 6, 15 and 9 is 21 × 32 × 51 = 2 × 3 × 3 × 5 = 90.
The L.C.M. of literal coefficients = The L.C.M. of p2q2, p3q and p2q3r = p3q3r
Since, in p2q2, p3q and p2q3r, we get
The highest power of p is p3.
The highest power of q is q3.
The highest power of r is r.
Therefore, the L.C.M. of p2q2, p3q and p2q3r = p3q3r.
Thus, the L.C.M. of 6p2q2, 15p3q and 9p2q3r
= The L.C.M. of numerical coefficients × The L.C.M. of literal coefficients
= 90 × (p3q3r)
= 90p3q3r.
Note:
According to the well known definition of L.C.M., the expression obtained as L.C.M should be the least expression which should be separately divisible by each and every expression and for this:
(i) the coefficient of the L.C.M. obtained should be equal to the L.C.M. of the coefficient of the given expressions.
(ii) the power of the each variable present in the L.C.M. should be equal to the highest power of that variable present in the given expressions.
Step-by-step explanation: