What is the LCM x³ + 4x²y + 4xy² and x²+ x y – 2y²?
Answers
Answer:
Step-by-step explanation:
What is the LCM x³ + 4x²y + 4xy² and Solved examples to find lowest common factor of polynomials:
1. Find the L.C.M. of 4a2 - 25b2 and 6a2 + 15ab.
Solution:
Factorizing 4a2 - 25b2 we get,
(2a)2 - (5b)2, by using the identity a2 - b2.
= (2a + 5b) (2a - 5b)
Also, factorizing 6a2 + 15ab by taking the common factor '3a', we get
= 3a(2a + 5b)
Therefore, the L.C.M. of 4a2 - 25b2 and 6a2 + 15ab is 3a(2a + 5b) (2a - 5b)
2. Find the L.C.M. of x2y2 - x2 and xy2 - 2xy - 3x.
Solution:
Factorizing x2y2 - x2 by taking the common factor 'x2' we get,
x2(y2 - 1)
Now by using the identity a2 - b2.
x2(y2 - 12)
= x2(y + 1) (y - 1)
Also, factorizing xy2 - 2xy - 3x by taking the common factor 'x' we get,
x(y2 - 2y - 3)
= x(y2 - 3y + y - 3)
= x[y(y - 3) + 1(y - 3)]
= x(y - 3) (y + 1)
Therefore, the L.C.M. of x2y2 - x2 and xy2 - 2xy - 3x is x2(y + 1) (y - 1) (y - 3).
3. Find the L.C.M. of x2 + xy, xz + yz and x2 + 2xy + y2.
Solution:
Factorizing x2 + xy by taking the common factor 'x', we get
x(x + y)
Factorizing xz + yz by taking the common factor 'z', we get
z(x + y)
Factorizing x2 + 2xy + y2 by using the identity (a + b)2, we get
= (x)2 + 2 (x) (y) + (y)2
= (x + y)2
= (x + y) (x + y)
Therefore, the L.C.M. of x2 + xy, xz + yz and x2 + 2xy + y2 is xz(x + y) (x + y).x²+ x y – 2y²?