Question

What is the least multiple of 7 which leaves a remainder of 4 when divided by 6, 9, 15 and 18?

Answer 1

L.C.M of 6,9,15,18 =90

let the required number be (90K+4) which is multiple of 7

least value of K for which (90K+4) is divisible by 7 is K=4

therfore required number =(90*4)+4 =364