Math, asked by adiswati, 9 months ago

what is the least no which when divided by tye numbers 3 5 6 8 10 and 12 leaves in each case 2 but which when divided by 13 leaves no rrmainder?​

Answers

Answered by nagendra1387
1

Answer:

The number is 962

Step-by-step explanation:

Lcm of ( 3,5,6,8,10,12) * K + 2

= 120K+2

120K +2 /13

=117K+3K +2/13

The least value of K for which this holds true is 8 (3*8+2 = 26)

Therefore the least such number is 120*8+2 = 962

Answered by sanjanasingh200207
0

Answer:

above answer is correct ....

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