Question

What is the least number of four digits when increased by 7 divisible by 35,48 and 56?

Answer 1

Answer:  The answer is 1673.

Step-by-step explanation:  We are to find the least number which when increased by 7, becomes divisible by 35, 48 and 56.

For doing so, we need to find the L.C.M.(least common multiple) of 35, 48 and 56.

We have

L.C.M.(35, 48, 56) = 7 × 8 × 5 × 6 = 1680.

Also, 1680 - 7 = 1673.

Thus, the required four digit number is 1673.