Question

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ?

A) 844 B) 814 C) 840 D) 820

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

• Floor of a room 15 m 17 cm long.

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• Floor of a 9 m 2 cm broad.

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$\red{\underline \bold{To \: Find:}}$

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• What is the least number of squares tiles required to pave the floor

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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$\underline{\bold{\texttt{Length of the room :}}}$

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⇛ 15 m 17 cm

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⇛ 15 × 100 + 17

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⇛ 1517 cm

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$\underline{\bold{\texttt{Breadth of the room :}}}$

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⇛ 9 m 2 cm

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⇛ 902 cm.

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The HCF of the 1517 and 902 will be size of square tiles.

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HCF 1517 and 902 = 41 cm.

Area of the room

⇛ length × breadth

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⇛ 1517 × 902 cm2

Area of tiles = 41 × 41 cm2

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So, number of tiles required

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$\sf \longmapsto \dfrac { 1517 \times 902 } { 41 \times 41 }$

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$\bf \dashrightarrow 814 \: tiles$

Answer 2

Step-by-step explanation:

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