Question

What is the least number that leaves a remainder of 2 when divided by 4, 6, and 8?

Answer 1

Step-by-step explanation:

24 is the right answer

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Answer 2

Concept:

The least common factor of any two is the value that is evenly divisible by the two given numbers.

Given:

And Divisors are 4, 6, and 8.

Remainder = 2

Find:

We are asked to find the least number that leaves a remainder of 2 when divided by 4, 6, and 8.

Solution:

We have,

Divisors are 4, 6, and 8.

Remainder = 2

Now,

We will first find the LCM of 4, 6, and 8.

For this, we will first make the factors of the numbers:

4 = 2 × 2

6  =2 × 3

8 = 2 × 2 × 2

We get the LCM as:

LCM = 2 × 2 × 2 × 3

LCM = 8 × 3

LCM = 24

Now let the number be x,

Since it leaves remainder 2, we get that:

x - 2 = 24

x = 24 + 2

x = 26

Therefore, we get the least number that leaves a remainder of 2 when divided by 4, 6, and 8 as 26.

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