What is the least number that must be subtracted from 2346 to make it exactly divisible by 5 ,7
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Answer:
1
Step-by-step explanation:
hi...
LCM of 7&5 is 35
when we divide 2346 by 35 ... we get remainder of 1
so, subtract 1 from 2346....becomes 2345
and 2345 is divisible by both 5&7
so answer is 1
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