Question

what is the least number that should be added to 37301 so that it is exactly dovisible by 27

Answer 1

Let the number to be added be x

So, x = remainder of 37301/27

By euclid's division lemma

a = bq + r

37301 = 27*q + r

You have to find the least value of q such that 27*q > 37301

If you divide, in this case q = 1382

then, x = 1382*27 - 37301

x = 13