Question

What is the least number to be multiplied with 16 to make it a perfect cube

Answer 1

$Given \: number \: is \: 16$

$Resolve \: 16 \: into \: product \: of \: prime$

$factors .$

16 = (2×2×2) ×2

Here, 2 doesn't appear in a group of three.

So, 16 is not a perfect cube.

Hence, the smallest number by which it is to be multiplied to make it perfect cube is 2 × 2 = 4

Therefore.,

$\red{ perfect \:cube }$

$= 16 \times 4$

$= 64$

$= 4^{3}$

$\red{ Required \: least \: number \: be}$

$\red{ multiplied \:with \:16 \:to \:make \: it \: a }$

$\red{ perfect \: cube} \green { \: is \: 4 }$

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