Question

What is the least number which is exactly divisible by 12,18 and 21 and leaves a remainder of 3?

Answer 1

Answer:

thanks for the points thanks for the points

Answer 2

$\huge\fbox\red{A}\fbox\purple{n}\huge\fbox\green{s}\fbox\orange{w}\huge\fbox\pink{e}\fbox\blue{r}$

Thus, the smallest 4 digit number such that when it is divided by 12, 18, 21 and 28 is 1008. Also, the required no. leaves remainder 3. Hence, the required number is 1011.