What is the least number which is when decreased by 5 is devisible by 12,16,and 20 ?
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Answer:
Step-by-step explanation:
Find the LCM of
12 = 2x2x3
16 = 2x2x2x2
18 = 2x3x3
21 = 3x7
28 = 2x2x7
The LCM is thus 2x2x2x2x3x3x7 = 1008.
Next add 7 to 1008 to get 1015, which is the number that needs to be decreased by 7 to be exactly divisible by 12,16,18,21 and 28.
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