Question

What is the least number which when diminished by 7 is divisible by each one of 21,28,36 and 45.​

Answer 1

Answer:

Let us find LCM of the given numbers by factorization method

21 = 7X3

28 = 7X2X2

36 = 2X2X3X3

45 = 3X3X5

So, the LCM is 2X2X3X3X5X7= 1260

So, the required least number when diminished by 7 and is divisible by 21,28,36,45 is 1260+7 =

1267