Question

(What is the least number which when divided by
12, 15, 20 & 54 leaves a remainder 4 in each case?​

Answer 1

Step-by-step explanation:

Thus, 548 is the least no which when divided by 12 15 20 and 54 leaves in each case a remainder.

Answer 2

Answer:

544

Step-by-step explanation:

Firstly, take out the L.C.M. of 12,15,20,54.

This prime factorization will give you,

2×2×3×3×3×5 = 4×9×15 = 60×9 = 540

Now, in each case the remainder is 4,

So the least number, which when divided by 12, 15, 20, 54 leave remainder of 4 in each case will be :

540+4 = 544

Ans. 544