Question

What is the least number which when divided by 12,15,20 and 24 gives the same remainder 7 in each case.

Answer 1

Answer 121577

Pls check my answer

Answer 2

Step-by-step explanation:

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,24

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️6

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️3

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×2

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️5

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×5

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️10

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️5

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×5

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×524/2➡️12

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×524/2➡️1212/2➡️6

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×524/2➡️1212/2➡️66/2➡️3

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×524/2➡️1212/2➡️66/2➡️324 = 2×2×2×2×3

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×524/2➡️1212/2➡️66/2➡️324 = 2×2×2×2×3THE LCM = 2×2×2×2×3×5= 240

FRIST WE HAVE TO GET THE LCM OF 12,15,20 AND ,2412/2➡️66/2 ➡️312 = 2×2×215/3➡️515=3×520/2➡️1010/2➡️520 = 2×2×524/2➡️1212/2➡️66/2➡️324 = 2×2×2×2×3THE LCM = 2×2×2×2×3×5= 240THE REQUIRED NUMBER = 240+7= 247