What is the least number which when divided by 257 and 9 leaves a remainder of 1 in each case?
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heya friend ✋✋
here's your answer....
257-1=256
9-1=8
256=2×2×2×2×2×2×2×2
8=2×2×2
therefore the least number(LCM OF 256 AND 8)=256
HOPE IT HELPS YOU ✌✌
here's your answer....
257-1=256
9-1=8
256=2×2×2×2×2×2×2×2
8=2×2×2
therefore the least number(LCM OF 256 AND 8)=256
HOPE IT HELPS YOU ✌✌
TANUJA5454:
hii
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