Math, asked by djhanjhariwal8367, 1 year ago

What is the least number which when divided by 3,5,6,8,10,12 leaves a remainder of 2 in each case but when divided by 13 leaves no remainder

Answers

Answered by amanraj56
9

Answer:

least no. divided by 3,5,6,8,10,12

giving no remainder is lcm of this no.

LCM of 3,5,6,8,10,12 is 120

we have to get 2 as a remainder

so we add 2 in LCM but contradict is that it must be divided by 13

so no. will be

120k+2

to find value of k

(120k+2)/13

(117k+3k+2)/13

117k/13 +(3k+2)/13

here 117k/13 give remainder as 0

in (3k+2)

on putting the value of k=8 it gives remainder as 0

no. will be 120k+2

120×8+2

960+2

962

hence the no. is 962

Answered by srir65616
1

Answer:

962

Step-by-step explanation:

l.c.m of 3, 5 , 6,8,10 is 120

therefore ( 120 k + 2 ) here 2 is remainder

(120 k + 2) divisible by 13 , in case where

k is equal to 8

therefore 120 into 8+2 equal to 962

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