What is the least number which when divided by 3,5,6,8,10,12 leaves a remainder of 2 in each case but when divided by 13 leaves no remainder
Answers
Answered by
9
Answer:
least no. divided by 3,5,6,8,10,12
giving no remainder is lcm of this no.
LCM of 3,5,6,8,10,12 is 120
we have to get 2 as a remainder
so we add 2 in LCM but contradict is that it must be divided by 13
so no. will be
120k+2
to find value of k
(120k+2)/13
(117k+3k+2)/13
117k/13 +(3k+2)/13
here 117k/13 give remainder as 0
in (3k+2)
on putting the value of k=8 it gives remainder as 0
no. will be 120k+2
120×8+2
960+2
962
hence the no. is 962
Answered by
1
Answer:
962
Step-by-step explanation:
l.c.m of 3, 5 , 6,8,10 is 120
therefore ( 120 k + 2 ) here 2 is remainder
(120 k + 2) divisible by 13 , in case where
k is equal to 8
therefore 120 into 8+2 equal to 962
Similar questions