what is the least number which when divided by 5, 7, and 11 leaves remainders 1, 2 and 3 respectively?
I know the answer, I need the steps. Let us see who solves it with proper steps
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Answer:
Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3
∴ The required Number = LCM of (4, 5, 6) – 3
= 60 – 3 = 57
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Step-by-step explanation:
5 - 1 = 4
7 - 2 = 5
11 - 3 = 8
Now we take out the LCM of 4, 5, and 8 = 40
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