Question

what is the least number which when divided by 5, 7, and 11 leaves remainders 1, 2 and 3 respectively?​

I know the answer, I need the steps. Let us see who solves it with proper steps​

Answer 1

Answer:

Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3

∴ The required Number = LCM of (4, 5, 6) – 3

= 60 – 3 = 57

Answer 2

Step-by-step explanation:

5 - 1 = 4

7 - 2 = 5

11 - 3 = 8

Now we take out the LCM of 4, 5, and 8 = 40