Question

what is the least number which when divided by 8 9 12 15 leaves a remainder of one in each case​

Answer 1

Answer: take the LCM of (given numbers)+add remainder

LCM(8,12,15,20)=120

add 5 which is remainder which gives 125

so, answer is 125.

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Step-by-step explanation:

Answer 2

The least number which when divided by 8, 9, 12 and 15 leaves a remainder of one in each case is 361.

Step-by-step explanation:

To find : The least number which when divided by 8, 9, 12 and 15 leaves a remainder of one in each case​?  

Solution :  

We find the LCM of 8, 9, 12 and 15.

2 | 8  9  12  15

2 | 4  9   6   15

2 | 2  9   3   15

3 | 1   9   3   15

3 | 1   3   1    5

5 | 1   1    1    5

  | 1   1    1     1

$LCM(8,9,12,15)=2\times 2\times 2\times 3\times 3\times 5$  

$LCM(8,9,12,15)=360$  

In each case it leaves a remainder 1 so we add 1 in the LCM of the numbers.

i.e. 360+1=361.

Therefore, the least number which when divided by 8, 9, 12 and 15 leaves a remainder of one in each case is 361.

#Learn more

What is the least number which when divided by each one of 6,9,15,18 leaves remainder 4 in each case and completely divisible by 7

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