what is the least number which when lessened by 6 is divisible by 36, 48 and 21
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2
Answer:
3
Step-by-step explanation:
36/3=12
48/3=16
21/3=7
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To find the least number, we need to find the LCM of 36,48,21 and 28.
36 = 2×2×3×3
48 = 2×2×2×2×3×3
21 = 3×7
28 = 2×2×7
Thus the LCM of these numbers is 2⁴ × 3² × 7 = 1008
The LCM of 36, 48, 21 and 28 is 1008.
When 5 is added to 1008 , we get 1013.
Hence, 1013 is the least number when decreased by 5 is divisible by 36, 48, 21 and 28.
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