Question

what is the least possible number which must be subtracted from 16,19 and 23 so that the resulting number are in continued proportion​

Answer 1

Answer:

The answer is 7

Step-by-step explanation:

let x be subtracted

Then, according to question,

16-x/19-x=19-x/23-x

on cross multiplying,

x^2-16x-23x+368=x^2-19x-19x+361

x^2 gets cancelled.

Then,

-39x+368= -38x+361

on transposing,

368-361= -38x+39x

7=x

therefore x=7

hope it helps you

thanks