what is the least possible number which when divided by 13 leaves a remainder 3 and when it is divided by 5 leaves a remainder 2.
Answers
According to the question we have to find the least number which when divided by 13 leaves a remainder of 3 and when divided by 5 gives a remainder of 2.
This question can be better answered by brute forcing the options.
Even if not then you can go for finding out the multiples of 13 as it is greater than 5 so it will take less time to reach the answer.
After getting each multiple of 13 you have to add 328 and check if it satisfies the second equation that is leaving remainder 2 when divided by 5 or not.
13 * 8 = 104.
Adding 3 to 104 we get 107.
107 is the least possible number which satisfies both the cases. i.e. leaves remainder 3 and 2 when divided by 13 and 5 respectively.
Therefore answer is 107.
Answer: 42
Step-by-step explanation: Let no. = x
x= 13k+3
If devided by 5 and leaves remainder 2 then
x=13k+3-2 (devided by 5 )
x=13k+1
Putting x=3 it devided by 5
So no. x=13×3+3
=42