What is the least value of p so that the number 6p545divisible by3
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Answer:
The least value of p which can fit in this equation is 1.
This is so because if you recall the divisibility test of three, the sum of all the digits of a number must be divisible by 3.
In this number:
6+p+5+4+5= a no. divisible by 3
6+5+4+5=20
The multiple of three nearest to 20 is 21.
21-20=p
1=p
Explanation:
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