What is the least velocity with which a cricket ball can be thrown through a distance of 100 m?
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Answer:
Maximum horizontal distance, R=100m
The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45
∘
, i.e., =45
∘
.
The max horizontal range for a projection velocity v is given by the relation:
R
max
=
g
u
2
100=
g
u
2
The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H.
Acceleration, a=g
Using the third equation of motion:
v
2
−u
2
=−2gH
H=u
2
/2g=100/2=50m
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