Question

What is the length, 1, of this piece of graphite, in centimeters?​

Answer 1

p = 2 × 10`⁴ Ωm

R = 10Ω

Area of cross section = 0.4mm² = 0.4 × 10`⁶ m²

• R = P× L/A

10 = (2 × 10`⁴) × L/(0.4 × 10`⁶)

[10 × (0.4 × 10`⁶) ] / (2 × 10`⁴) = L

(0.4 × 10`⁶)/(2 × 10`³)= L

0.2 × 10^(-6 - (-3)) = L

0.2 × 10^(-6 + 3) = L

0.2 × 10`³ = L

L = 0.2 × 10`³ m

L = 0.2 × 10`³m = 0.2 × 10`³/10² cm = 0.2 × 10`⁵cm

L = 0.2 × 10`⁵ cm