Question

what is the length and breadth if perimeter is 60 cm and area is 900 square cm?​

Answer 1

Answer:

formula =L = leangth

B= Breadth

leangth is multiplied by breadth

Answer 2

Answer:

perimeter of rectangle= 2(l+b)

area of rectangle          =(l*b)

ATQ⇒

• 2(l+b)=60

•  l+b  =$\frac{60}{2}$

• l+b  =  30
•   l  =   30-b .....(1)

now

• l*b=900      ......(2)

substitute {  "l=30-b" } in (2)

(30-b)b =900

30b-b² = 900

• by rearranging; we have

b²-30b+900 = 0

now by   { (-b)±$\sqrt{(b*b)-4ac}$ }÷ 2a

we have {-(-30)±$\sqrt{30*30-4*1*900}$ }÷ 2*1

     = (30 ±$\sqrt{2700}$ )÷ 2

• by solving further we have

≈ (30±52)÷2                          

    (30+52)÷2                                    (30-52)÷2

   =  82 ÷ 2                                         = -22 ÷ 2

   =41                                                  =  (-11)

   so the values are 41 and -11

{note: please do not depend on this answer without verification}