Question

What is the length and breadth of the rectangle whose area is 4a2

+ 4a -3, (a>0) ?
answer in detail.​

Answer 1

Answer:

Given:-

• Area of rectangle = 4a² + 4a - 3

Find:-

• Length and breadth of rectangle?

Solution:-

• First we have to factorise the area of rectangle
• Then we will get the length and breadth
• Area = length × Breadth

$: { \implies { \sf{4 {a}^{2} + 4a - 3 }}}$

$:{ \implies{ \sf{4 {a}^{2} + 6a - 2a - 3 }}}$

$: { \implies{ \sf{2a(2a + 3) - 1(2a + 3)}}}$

$: { \implies{ \sf{ \bold{(2a + 3)(2a - 1)}}}}$

By this we can understand that ,

Length × Breadth = (2a + 3) (2a - 1)

Case(1) :-

length = 2a + 3 ; Breadth = 2a - 1

Case(2) :-

length = 2a - 1 ; Breadth = 2a + 3

Answer 2

Step-by-step explanation:

4a2 + 4a- 3 (a>0)

= (4×a×2) + (4×a-3)

= a×8 + 4×a-3

= 2a = 8+4-3

= 2a = 9

= a = 9/2

= a = 4.10