Question

What is the length and breadth of the rectangle whose area is 4a²+ 4a −

3,(a > 0)?​

Answer 1

Answer:

area of rectangle is= length X breadth

so it length and breadth can be factor of this expression.

\begin{gathered}4 {a}^{2} + 4a - 3 \\ 4 {a}^{2} + 6a - 2a - 3\end{gathered}4a2+4a−34a2+6a−2a−3

\begin{gathered}2a(2a + 3) - 1(2a + 3) \\ (2a + 3)(2a - 1)\end{gathered}2a(2a+3)−1(2a+3)(2a+3)(2a−1)

so length can be :(2a+3)

breadth can be :(2a-1)