what is the length of a rectangle 11 cm wide if its perimeter is 52 cm
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Answered by
1
Answer:
here, breadth of the rectangle is given 11 cm and
perimeter is given as 52 cm
perimeter of rectangle = 2(l+b)
52 = 2 x ( l + 11 )
52/2 = l + 11
26 = l + 11
l = 26 - 11
l = 15
therefore the length of the rectangle is 15 cm
Answered by
0
Step-by-step explanation:
b=11cm
p=52cm
let length of rectangle be l
so,
perimeter of rectangle=2(l+b)
52=2(l+11)
52/2=l +11
26=l + 11
l= 26-11
l=15
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