Question

what is the length of a rectangle 11 cm wide if its perimeter is 52 cm​8

​

Answer 1

Perimeter $= 2(l + b) \\ 52 \: cm {}^{2} = 2(l + 11) \\ {52 \: cm}^{2} = 2l + 11 \\ 52 - 11 = 2l \\ 42 = 2l \\ l = 21$

Answer 2

Step-by-step explanation:

Perimeter = 2 ( l+ b)

52cm^2 = 2( l+ 11)

52/2 = l+ 11

26 = l+ 11

length = 26 -11= 15