what is the length of a rectangle if its perimeter is 28cm and the breadth is 6cm.
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What is the length of a diagonal of a rectangle whose perimeter is 28 cm and breadth is 6 cm?
Kolly Adex
Answered August 30, 2019
Perimeter = 2(l+b)
Where l = length
b = breadth
28 = 2(l+b)
28 = 2(l+6)
28 = 2l + 12
2l = 28 - 12
2l = 16
l = 16/2 = 8 cm
Diagonal of a rectangle: It is a line that joins two opposite angles of a rectangle. It also divides a rectangle into two equal triangles. It is the common hypotenuse side for the two equal triangles.
Applying the Pythagorean theorem:
Opposite side = 8 cm
Adjacent side = 6 cm
Hypotenuse side = ?
(Hypotenuse)^2 = (Opposite)^2 + (Adjacent)^2
On finding the square root of both sides
Hypotenuse = Sqrt((Opposite)^2 + (Adjacent)^2)
Hypotenuse = Sqrt((8)^2 + (6)^2)
Hypotenuse = Sqrt(64 + 36)
Hypotenuse = Sqrt(100)
Hypotenuse side (diagonal) = 10 cm
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