Question

:What is the length of a Seconds' pendulum at a place where g= 9.6 m/s^2 . ​

Answer 1

Step-by-step explanation:

by using formula

T=2pi Rootl/g

$t = 2\pi \sqrt{l \div g}$

t=2pirootl/9.6

t=9.8x10

9.8x10=2pirootl/9.6

4.9x10=pirootl/9.6

root (49)²x9.6/pi=l

l solve this u get urs answer perfectly