What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?
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The length is =1.20144m
=
1.20144
m
Explanation:
The coefficient of linear expansion of aluminium is
alpha=24*10^-6 (ºC)^-1
Therefore
DeltaL=alphaLDeltaT
=24*10^-6*1.2*(65-15)
=1440*10^-6m
=1.44*10^-3
The length is
L+DeltaL=1.2+0.00144=
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