Question

What is the length of attitude of a triangle whose area is 21cm square and base is 6 cm

Answer 1

$\textbf{\underline{\underline{Answer :- }}}$

The altitude of the triangle is 7 cm.

$\textbf{\underline{\underline{Explanation :-}}}$

Given :

Area of the triangle = 21 sq.cm

Base of the triangle = 6 cm

To find :

The Length of the altitude of the triangle

Solution :

As we know :

$\star$ Area of triangle :

${\boxed{\sf\:{Area = \dfrac{1}{2} \times base \times height}}}$

$\sf{\implies \: 21 \: sq.cm \: = \dfrac{1}{2} \times6 \times x }$

$\sf{\implies21 = 3 \times x}$

$\sf{\implies3x = 21}$

$\sf{\implies \: x = \dfrac{21}{3} }$

$\sf{\implies \: x = 7}$

${\boxed{\bigstar{\sf\:{Height = 7 \: cm}}}}$

$\therefore$The altitude of the triangle is 7 cm.

$\textbf{\underline{\underline{Verification :-}}}$

$\sf{\implies \: 21 \: sq.cm \: = \dfrac{1}{2} \times6 \times 7 }$

$\sf{\implies \: 21 \:\: = 7 \times 3}$

$\sf{\implies \: 21 = 21 }$

When we placed the value of x (7) we got the required answer 21.

${\boxed{\sf\:{LHS = RHS}}}$

$\therefore$The altitude of the triangle is 7 cm.

Answer 2

Answer is here for u mate !!!

The altitude is

Wondering how ??? Explanation is here mate !!!!

Area = ½ × b × h

21 = ½ × 6 × h

21 = 3h

h = 21 ÷ 3

h = 7

Altitude = 7 cm