Question

what is the length of conductor which moves with a speed of 10 m/s in the direction perpendicular to the direction of magnetic field of induction 0.8T if it induces an emf of 8v between the ends of conductor​

Answer 1

Explanation:

Explanation:

Given :

A speed of 10 m/s in the direction perpendicular .

the direction of magnetic field of induction 0.8T

if it induces an emf of 8v between the ends of conductor

To Find :

what is the length of conductor which moves

Solution :

Concept :

The formula of effective EMF and effective internal

So, V = ε – Ir,

where V is the potential difference across the circuit, ε is the emf, I is the current flowing through the circuit, r is internal resistance.

______________________

\begin{gathered}: \implies \sf \: \: \: \: \: \: \: \: \xi = blv \\ \\ \\ : \implies \sf \: \: \: \: \: \: \: \:l = \frac{ \xi}{bv} \\ \\ \\\end{gathered}

:⟹ξ=blv

:⟹l=

bv

ξ

Substitute all values :

\begin{gathered}: \implies \sf \: \: \: \: \: \: \: \: l = \frac{8}{0.8 \times 10} \\ \\ \\ : \implies \sf \: \: \: \: \: \: \: \: l = \cancel{\frac{8}{8}} \\ \\ \\ : \implies \sf \: \: \: \: \: \: \: \: l =1 m\end{gathered}

:⟹l=

0.8×10

8

:⟹l=

8

8

:⟹l=1m

Hence the value of length is 1 m