Question

what is the length of cube with density of BCC crystal 3.11g/cc and M=60​

Answer 1

Answer:

CORRECT ANSWER IS 217 pm

Explanation:

Theoretical density of crystal is given by ρ=Noa3nM g/cm3

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3⇒n=752×6.022×1023×(5)3×(10−8)3=2

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3⇒n=752×6.022×1023×(5)3×(10−8)3=2So, it is body centered cubic (BCC) structure. For BCC, if a is the edge length of the cube and r is the radius of the atom then,

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3⇒n=752×6.022×1023×(5)3×(10−8)3=2So, it is body centered cubic (BCC) structure. For BCC, if a is the edge length of the cube and r is the radius of the atom then,4r=3a

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3⇒n=752×6.022×1023×(5)3×(10−8)3=2So, it is body centered cubic (BCC) structure. For BCC, if a is the edge length of the cube and r is the radius of the atom then,4r=3a⇒r=43a

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3⇒n=752×6.022×1023×(5)3×(10−8)3=2So, it is body centered cubic (BCC) structure. For BCC, if a is the edge length of the cube and r is the radius of the atom then,4r=3a⇒r=43a=43×5 A˚

Theoretical density of crystal is given by ρ=Noa3nM g/cm3⇒n=MρN0a3⇒n=752×6.022×1023×(5)3×(10−8)3=2So, it is body centered cubic (BCC) structure. For BCC, if a is the edge length of the cube and r is the radius of the atom then,4r=3a⇒r=43a=43×5 A˚⇒r=2.165 A˚=2.165×10−8 cm=216 pm