Question

what is the length of diagonal of a square which has the side length as 4cm?​

Answer 1

Answer:

$\sqrt[4]{2}$

Step-by-step explanation:

using pythagoras theorem

let base=4cm=(b)

let height=4cm=(h)

therefore,we know-

${4}^{2} + {4}^{2} = \\ square \:of \: hypotenuse$

therefore

$\sqrt{32} = \sqrt[4]{2}$

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