What is the length of either of the remaining equal sides?
1. Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
5. Two numbers are in the ratio 5:3. If they differ by 18, what are the numham?
Answers
SOLUTION - 1 :
Given,
Sum of two numbers = 95
one exceeds the other by 15
let one number be x
Another number = x + 15
According to the problem,
x + x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
One number = x = 40
Another = x + 15 = 95
SOLUTION - 2 :
Given,
Ratio of two numbers = 5:3
difference between the two numbers = 18
let the ratios be 5x and 3x
According to the problem,
5x - 3x = 18
2x = 18
x = 18/2
x = 9
One number = 5x = 5(9) = 45
Another number = 3x = 3(9) = 27
SOLUTION - 1 :
Given,
Sum of two numbers = 95
one exceeds the other by 15
let one number be x
Another number = x + 15
According to the problem,
x + x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
One number = x = 40
Another = x + 15 = 95
SOLUTION - 2 :
Given,
Ratio of two numbers = 5:3
difference between the two numbers = 18
let the ratios be 5x and 3x
According to the problem,
5x - 3x = 18
2x = 18
x = 18/2
x = 9
One number = 5x = 5(9) = 45
Another number = 3x = 3(9) = 27