What is the length of FG, where FG is parallel to side BC ?
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Step-by-step explanation:
as IN TBC, TC=TB=BC=12M
so, angle T, B, C are 60 degree
but G is midpoint of TC so, TG=6 cm
F is midpoint of TB so, TF=6 cm
As angle A is 60 degree and TF and TG are equal so angle F, G are equal and 2x+60=180
x=60
so that TFG IS a equilateral triangle that's why TF=FG=GT=6 m
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