What is the length of median AD if AB and AC are resp. represented by I+j and 3i+j-4k?
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Answer:
AB+BC=AC
or, BC=AC-AB= (3i+j-4k)-(i+j)=2i-4k
BD=BC/2=i-2k
AB+BD=AD
or,AD= i+j+i-2k=2i+j-2k
Length of AD=√{2²+1²+(-2)²}=3
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