Question

what is the length of Po in the. parallelogram ef 00=6cm and the diagonal PR is half the diagonal of SQ?​

Answer 1

Solution:

Length of the two diagonals will be

⇒ d1=∣(5a+2b)+(a−3b)∣

⇒ d2=∣(5a+2b)−(a−3b)∣

⇒ d1=∣6a−b∣ and ⇒ d2=∣4a+5b∣

So,

d1=∣6a∣2+∣−b∣2+2∣6a∣∣−b∣cos(π−4π)

d1=36(22)2+32+12(22)3(−21)

d1=15

d2=∣4a∣2+∣5b∣