Question

what is the length of rectangle if its breadth half of its length and its perimeter is 60 centimetre?? Solve step by step​

Answer 1

Answer:

20 cm, 10 cm

Step-by-step explanation:

Perimeter of rectangle = 2(length+breadth)

Breadth = 1/2 length

Let length be 2x

Breadth = x

2(2x+x)=60

2(3x)=60

6x=60

X = 60/6 = 10

Breadth is 10 cm

Length = 2x = 20 cm

20 cm and 10 cm

Answer 2

Answer:

the length of the rectangle (l) = 20 cm. the breadth of the rectangle (b) = X/2 = 20/2 = 10cm.

Step-by-step explanation:

The given the length of rectangle if its breadth half of its length and its perimeter is 60 centimetre

so, let us take the length of the rectangle (l) be = X cm.

the breadth of the rectangle (b) be = X/2 cm.

the perimeter of the rectangle = 60 cm.

The formula for the perimeter of the rectangle is =[P=2(l+b)]

=> 2 (X + X/2) =60

=> 2X + 2 × X/2 = 60

=> 2X + X = 60

=> 3X = 60

=> X = 60/3

=> X = 20.

Hence X = 20.

then, the length of therectangle(l)=20cm.

the breadth of the rectangle (b) = X/2 = 20/2 = 10cm.

so, let us check P = 2 ( 20 +10 )

P = 2 ( 30 )

P = 60 cm.

I Hope it helps you ☺️