Question

What is the length of the chord of a circle represented by x^2+4x+4+y^3+6y+9=9 passing through the centre?

Answer 1

Answer:

Step-by-step explanation:

Equation of a circle is x^2+y^2–4x-6y-12=0.

or,. (x - 2)^2 + (y - 3)^2 = 12+4+9. = (5)^2.

Thus, the centre of the circle is (2,3) and radius is 5 units.

Equation of the diameter of the circle which passes through (0,0) and (2,3) is :-

(y - 0)/(x - 0) = (3–0)/(2–0).

or, 3.x = 2.y.

or,. 3.x - 2.y = 0. Answer.