Question

What is the length of the greatest rod that can be placed in a room whose length is 10 m, breadth 8 m an
height 6 m. Given that V2 = 1.42.
(1) 13.2
2) 14.2
(3) 15.2.
(4) 16.2
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Answer 1

Answer:

Length of the greatest (i.e. longest ) rod which can be placed in a room

= length of the diagonal

$= \sqrt{I²+b²+b²}$

$= \sqrt{10²+8²+6²}$

$= \sqrt{200}$

$= 10 \sqrt{2} \: \: meter$

=10 x 1.42m

=14.2 m

$\huge \mathfrak{Hope \: \: it \: \: Helps!}$