Question

What is the length of the hypotenuse , if the area of an isosceles right triangle is as given below :
AREA=8cmx^{2}

Answer 1

Area of an isosceles triangle

1/2 × (base × height)

8 = 1/2 (Base x Base)

8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]

8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒  Base= 4 cm

8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒  Base= 4 cm

8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒  Base= 4 cmIn ΔABC, using Pythagoras theorem

8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒  Base= 4 cmIn ΔABC, using Pythagoras theoremAC² = AB2²+ BC² = 42 + 42 = 16 + 16

= 42 + 42 = 16 + 16⇒ AC² = AC² = 32 = AC = ROOT 32