Question

what is the length of the hypotenuse of a right triangle if each of the two legs is 4 units?
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Answer 1

AnswEr :

• The length of the hypotenuse of a right angle triangle is 5.65 cm.

Explanation :

We are given with the base as well as perpendicular of a right angle triangle and given that each of the two legs is 4 unit, that is,

• Base = Hypotenuse = 4 cm.

We have to find out the length of the hypotenuse of a right angle triangle$.$

Now,

As we are given with base of a right angle triangle and perpendicular of a right angle triangle we know the required formula, that is,

→ (Hypotenuse)² = (Base)² + (Perpendicular)²

Substituting the given values in the formula,

→ (H)² = (B)² + (P)²

→ (H)² = (4)² + (4)²

→ (H)² = 16 + (4)²

→ (H)² = 16 + 16

→ (H)² = 32

→ H = √32

→ H = 5.65

Hence, the length of the hypotenuse of a right angle triangle is 5.65 cm.

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⠀⠀⠀Additional information :

Some important properties of right angle triangle :

• A right angle triangle has 3 sides, base, hypotenuse, and perpendicular.

• In right angle triangle one angle is always 90°.

• In right angle triangle opposite angle 90° is the hypotenuse.

• The hypotenuse is always the longest side in right angle triangle.

• The sum of other two interior angle is 90°.

• The sum of all three angles of a right angle triangle is 180°.

Answer 2

Answer:

$\huge \mathfrak {Given}$

Length of two legs - 4 units

$\huge \mathfrak {To \: find}$

Hypotenuse of triangle

$\huge \mathfrak {Solution}$

Here, it is given that it is a right angled triangle. And the unit of two legs = 4 unit.

As we know that

$\huge \bf \: {P}^{2} = {B}^{2} + {H}^{2}$

Here,

H= Hypotenuse

B = Base

P = Perpendicular

Putting the values

$\tt \mp \: {H}^{2} = {4}^{2} + {4}^{2}$

$\tt \mp \: {H}^{2} = 16 + 16$

$\tt \mp \: {H}^{2} = 32$

$\tt \mp \: H= \sqrt{32}$.

${\huge {\boxed {\red {\mathfrak {H = 5.65 \: cm}}}}}$