Question

What is the length of the largest pole that can be placed in a room 11m long, 8m broad and 9m high? *​

Answer 1

Answer:

17 m

Step-by-step explanation:

Length of pole = Length of diagonal (d)

Now,

By applying Pythagoras theorem , in the right triangle given in figure whose base is d1 and hypotenuse is d and height is same as height of room which is given to us as c = 9 m.

d(square) = 9(square) + d1(square). [equation 1]

Now first we need to find d1 ,

Again apply Pythagoras theorem , on the right triangle whose base is a = 12 m ,hypotenuse is d1 and height is b = 8 m.

d1(square) = b(square) + a(square)

d1(square) = 8(square) + 12(square)

d1(square) = 64 + 144 + 208

Hence , d1 = sq. root(208) = 14.422 m

Now putting this value of d1 in [equation 1],

d(square) = 9(square) + 14.422(square)

d(square) = 81 + 208 = 289

Now, d = sq. root(289) = 17 m