What is the length of the non-parallel sides in an isosceles trapezium if the perimeter is
256 cm and the lengths of the two parallel sides are 60 cm and 86 cm respectively?
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R.E.F. Image.
we know attitude is also a median in equilateral triangle.
BG = GC = 3 cm.
from ΔABG by Pythagoras theorem.
(AB)
2
=(AG)
2
+(BG)
2
(6)
2
=(AG)
2
+(3)
2
(AG)=
36−9
AG=
27
=5.20cm.
Height of trapezium = 2.60 cm → (given in question ⇒
2
5.20
=2.60cm)
Area of trapezium -
2
(a+b)×h
=
2
(6+3)×2.60
=9×1.3=11.70cm
2
.
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