Question

what is the length of the perpendicular in a right angled triangle If the hypotenuse is 13cm and base 12cm​.

Answer 1

Answer:

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Step-by-step explanation:

a+b+5=12

a+b=7⇒a=7−b...(1)

a

2

+b

2

=5

2

a

2

+b

2

=25...(2)

From (1) and (2)

(7−b)

2

+b

2

=25

49+b

2

−14b+b

2

=25

2b

2

−14b+24=0

b

2

−7b+12=0

(b−4)(b−3)=0

⇒b=4,3

a=7−b⇒a=3,4

Area=

2

1

×4×3=6sq. units

Answer 2

Answer:

Step-by-step explanation:

Hypotenuse=13cm

Base=12cm

Altitude(length of the perpendicular)=?

Let the altitude be h

Hypotenuse^2=base^+altitude^2

So 13^2=12^2+h^2

169=144+h^2

h^2=169-144

h=√25

h=5cm